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Инструкция по эксплуатации Napoleon Fireplaces, модель BGDV42N

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and 90° offset has a zero value and is shown in the formula as -45° and -90. respectively or -135. when combined. HORIZONTAL TERMINATION when (HT) < (VT) Simple venting configuration (only one 45. and 90° elbow) FIGURE 5 45. 90° REQUIRED VERTICAL RISE INFEET (VT) CALCULATED HORIZONTAL VENT RUN PLUS OFFSETS IN FEET (HT) The shaded area within the lines represents acceptable values for HT and VT . For vent configurations requiring more than one 45. and 90° elbow, the following formulas apply: Formula 1: H < V T T Formula 2: H + V < 40 feet T T Example 1: 90° H 2 V FIGURE 6 1 45. H 1 90° V 1 =8 ft V T = V 1 = 8 ft H 1 = 2.5 ft H 2 =2 ft H R = H 1 + H 2 = 2.5 + 2 = 4.5 ft H O =.03(one 45. elbow + two 90. elbows - 135.) =0.3(225-135.) = 2.7ft H T = H R + H O = 4.5 + 2.7 = 7.2 ft H T + V T = 7.2 +8 =15.2ft Formula 1: H T < V T 7.2 < 8 Formula 2: H T + V T < 40 feet 15.2 < 40 Since both formulas are met, this vent configuration is acceptable. W415-0381 / C / 05.13.04 HORIZONTAL TERMINATION HORIZONTAL TERMINATION when (HT) > (VT) Simple venting configuration (only one 45. and 90° elbow) See graph to determine the required vertical rise VT quired horizontal run HT. for the re-FIGURE 7 REQUIRED VERTICAL RISE IN INCHES (VT) HORIZONTAL VENT RUN PLUS OFFSETS IN FEET (HT) The shaded area within the lines represents acceptable values for H and V TT . For vent configurations requiring more than one 45. and 90° elbow the following formulas apply: Formula 1: HT < 4.2 VT Formula 2: HT + VT < 24.75 feet V1H90° H3H190° H290°FIGURE 8 45°V2 Example 2: V 1 =4 ft V 2 = 1.5 ft V = V + V = 4 ft + 1.5 ft = 5.5 ft T1 2 H 1 =2 ft H 2 =1 ft H 3 =1 ft H 4 = 1.5 ft H = H + H + H + H = 2 + 1 + 1 + 1. 5 = 5.5 ft R 12 34 H O = .03(one 45. elbow + three 90. elbow -135.) =.03(315-135)=5.4ft H T = H R + H O = 5.5 +5.4 = 10.9 ft H T + V T = 10.9 + 5.5 = 16.4 ft Formula 1: H < 4.2 V T T 4.2 V T = 4.2 x 5.5 = 23.1 ft 10.9 < 16.8 Formula 2: H + V < 24.75 feet T T 16.4 < 24.75 Since both formulas are met, this vent configuration is acceptable. W415-0381 / C / 05.13.04 VERTICAL TERMINATION VERTICAL TERMINATION when (HT) < (VT) Simple venting configurations FIGURE 9 45° See graph to determine the required vertical rise V T for the required horizontal run H T . REQUIRED VERTICAL RISE IN FEET (VT) HORIZONTAL VENT RUN PLUS OFFSETS IN FEET (HT) The shaded area within the lines represents acceptable values for HT and VT. For vent configurations requiring more than one 45. and one 90° elbow , the following formulas apply: Formula 1: H < V T T Formula 2: H + V < 40 feet T T Example 3: FIGURE10 V 2 45° V 1 90° H 2 90° H 1 90° V 1 =5 ft V 2 =10 ft V T = V 1 + V 2 = 5 + 10 = 15 ft H 1 =3 ft H 2 =2.5 ft H R = H 1 + H 2 = 3 + 2.5 = 5.5 ft H O = .03(one 45. elbow + three 90. elbows - 135.) = .03(45+90+90+90-135)=5.4 H T =H R + H O = 5.5 + 5.4 = 10.9 ft H T + V T = 10.9 + 15 = 25.9 ft Formula 1: H T < V T 10.9 < 15 Formula 2: H T + V T < 40 feet 25.9 < 40 Since both formulas are met, this vent configuration is acceptable. W415-0381 / C / 05.13.04 VERTICAL TERMINATION when (HT) > (VT) Simple venting configurations FIGURE 11 See graph to determine the required vertical rise V T for the required horizontal run H T . REQUIRED VERTICAL RISE IN FEET (VT) HORIZONTAL VENT RUN PLUS OFFSET IN FEET (HT) The shaded area within the lines represents acceptable values for HT and VT. For vent configurations requiring more than one 45. and one 90° elbow , the following formulas apply: Formula 1: H < 3V T T Formula 2:H + V < 40 feet T T Example 4: H190° FIGURE 12 45° V190° V290° H2 V 1 =1 ft V 2 =1.5 ft V T = V 1 + V 2 = 1 + 1.5 = 2.5 ft H 1 =6 ft H 2 =2 ft H R = H 1 + H 2 = 6 + 2 = 8 ft H O = .03(one 45. elbow + three 90. elbow - 135.) =.03(45 + 90 + 90 + 90 - 135) = 5.4 ft H T =H R + H O = 8 + 5.4 = 13.4 ft H T + V T = 13.4 + 2.5 = 15.9 ft Formula 1: H T < 3V T 3V T = 3 x 2.5 = 7.5 ft 13.4 > 7.5 Since this formula is not met, this vent configuration is unacceptable. Formula 2: H T + V T < 40 feet 15.9 < 40 Since only formula 2 is met, this vent configuration is unacceptable and a new fireplace location or vent configuration will need to be established to satisfy both formulas. Example 5: FIGURE 13 45° 45° 90° 90° H1H290°H3V2V1 V 1 =1.5 ft V 2 =8 ft V T = V 1 + V 2 = 1.5 + 8= 9.5 ft H 1 =1 ft H 2 =1 ft H 3 =10.75 ft H = H + H + H = 1 + 1 + 10.75 = 12.75 ft R 123H O = .03(three 90° elbows + two 45° elbow - 135°) =.03(90 + 90 + 90 + 45 + 45 - 135) = 6.75 ft H T =H R + H O = 12.75 + 6.75 = 19.5 ft H T + V T = 19.5 + 4.5= 29 ft Formula 1: H T < 3V T 3V T = 3 x 9.5 = 28.5 ft 19.5 < 28.5 Formula 2: H T + V T < 40 feet 29 < 40 Since both formulas are met, this vent configuration is acceptable. W415-0381 / C / 05.13.04 13 W415-0381 / C / 05.13.04 This application occurs when venting through a roof. Installation kits for various roof pitches are available from your Napoleon dealer. See Accessories to order the specific kit required. 1. Determine the air terminal location, cut and frame 10 in...